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12x^2-61x+70=0
a = 12; b = -61; c = +70;
Δ = b2-4ac
Δ = -612-4·12·70
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-19}{2*12}=\frac{42}{24} =1+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+19}{2*12}=\frac{80}{24} =3+1/3 $
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